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Writing Polynomial Equations from Graphs: Roots, Multiplicity, and End Behavior

Learn to read x-intercepts, touch/cross behavior, and end behavior from polynomial graphs to write factored equations and identify degree.

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Four exercises
Worked answers

Algebra and Function Practice

A polynomial graph encodes its equation through three visible features: where it meets the x-axis, whether it crosses or touches at each intercept, and how its ends behave. This lesson teaches a reliable procedure for translating those features into a factored polynomial equation. You will practice distinguishing odd and even multiplicity, using end behavior to determine the leading coefficient's sign and the degree's parity, and checking your equation against the graph. The focus is on writing equations from graphs, not on graphing from equations or solving equations.

Practice materials: Printable downloads are not available for this lesson yet. Use the instructions and four exercises below.

Reading Roots and Multiplicity from Intercepts

Each x-intercept of a polynomial graph corresponds to a real root and therefore a factor of the form (x - r). If the graph crosses the x-axis at r, the multiplicity of that root is odd; if it touches the axis and turns back, the multiplicity is even. The smallest odd multiplicity is 1 and the smallest even multiplicity is 2, so a crossing with no flattening suggests multiplicity 1, while a touch suggests multiplicity 2 unless the graph flattens more dramatically.

Multiplicity also affects the shape near the intercept. A root of multiplicity 1 crosses at a nonzero angle. A root of multiplicity 2 touches and turns, resembling a parabola near the point. A root of multiplicity 3 crosses but flattens momentarily, resembling a cubic near the point. Use these local shapes as evidence, but confirm with end behavior and degree.

  1. List every x-intercept r from left to right.
  2. At each intercept, decide whether the graph crosses or touches the x-axis.
  3. Assign the smallest consistent multiplicity: 1 for a simple cross, 2 for a touch, 3 for a flattening cross.
  4. Write a factor (x - r) raised to the assigned multiplicity for each intercept.

Using End Behavior to Fix Degree Parity and Leading Sign

End behavior tells you whether the polynomial degree is even or odd and whether the leading coefficient is positive or negative. If both ends rise or both ends fall, the degree is even. If one end rises and the other falls, the degree is odd. If the right end rises, the leading coefficient is positive; if the right end falls, it is negative.

Combine the sum of multiplicities with end behavior. The sum of multiplicities at real intercepts gives the minimum possible degree. If that sum already matches the parity required by end behavior, the degree may equal the sum. If not, add 1 to the degree by increasing one multiplicity by 1 or by including an additional non-real factor, but only when the graph supports it. In this lesson, graphs are designed so the sum of visible multiplicities matches the required parity.

  1. Observe the far-left and far-right directions of the graph.
  2. Decide even degree if ends match, odd degree if they oppose.
  3. Decide positive leading coefficient if the right end rises, negative if it falls.
  4. Add the multiplicities from all intercepts to get the minimum degree.
  5. Check that the minimum degree has the parity required by end behavior.

Assembling and Checking the Factored Equation

Write the equation as f(x) = a times the product of factors (x - r)^m, where m is the multiplicity at r. The constant a controls vertical stretch and reflection. Use end behavior to choose the sign of a, and use one additional point on the graph to determine its magnitude if needed. For many worksheet graphs, a is 1 or -1, but always verify with a test point.

Check your equation by substituting a point that is not an intercept. For example, in the worked example the graph passes through (0, 6); substitute x = 0 into f(x) = -(x + 2)(x - 1)^2(x - 3) and confirm the output is 6. Also confirm that the number of factors and their exponents produce the degree you identified. A correct equation should reproduce the intercepts, the touch/cross behavior, and the end behavior.

  1. Write f(x) = a times each factor with its multiplicity.
  2. Use end behavior to set the sign of a.
  3. Substitute a clear point from the graph to solve for the magnitude of a.
  4. Expand only if the task asks for expanded form; otherwise leave factored.
  5. Verify intercepts, local behavior, and end behavior against the graph.

Worked example

A polynomial graph crosses the x-axis at x = -2, touches at x = 1, and crosses at x = 3. Both ends fall. The graph passes through (0, 6). Write a factored equation and state the degree.

Worked answer

f(x) = -(x + 2)(x - 1)^2(x - 3), degree 4.

Why: Cross at -2 gives factor (x + 2) with multiplicity 1. Touch at 1 gives (x - 1)^2 with multiplicity 2. Cross at 3 gives (x - 3) with multiplicity 1. Sum of multiplicities is 1 + 2 + 1 = 4, which is even, matching the end behavior that both ends fall. Write f(x) = a(x + 2)(x - 1)^2(x - 3). Substitute (0, 6): 6 = a(0 + 2)(0 - 1)^2(0 - 3) = a(2)(1)(-3) = -6a, so a = -1. Thus f(x) = -(x + 2)(x - 1)^2(x - 3). The degree is 4, and the negative leading coefficient with even degree makes both ends fall, consistent with the graph.

Check: Substitute x = 0 into f(x) = -(x + 2)(x - 1)^2(x - 3): -(2)(1)(-3) = 6, matching the given point. Confirm the degree is 4 (even) and the leading coefficient is negative, so both ends fall.

Four practice exercises

Exercise 1

A polynomial graph crosses the x-axis at x = -1 and x = 4, and touches at x = 2. Both ends fall. The graph passes through (0, 8). Write a factored equation and state the degree.

Show answer and check

f(x) = -(1/2)(x + 1)(x - 2)^2(x - 4), degree 4.

Why: Cross at -1 gives (x + 1); touch at 2 gives (x - 2)^2; cross at 4 gives (x - 4). Sum of multiplicities is 1 + 2 + 1 = 4, even, matching both ends falling. Substitute (0, 8): 8 = a(1)(4)(-4) = -16a, so a = -1/2. The leading coefficient is negative, consistent with both ends falling. Degree 4.

Check: Substitute x = 0 and confirm the output is 8; confirm degree 4 is even and the leading coefficient is negative so both ends fall.

Exercise 2

A polynomial graph crosses at x = -3 with a flattening shape, crosses at x = 0, and crosses at x = 5. The left end falls and the right end rises. Write a factored equation with leading coefficient 1 and state the degree.

Show answer and check

f(x) = (x + 3)^3 x (x - 5), degree 5.

Why: Flattening cross at -3 suggests multiplicity 3. Cross at 0 gives x^1. Cross at 5 gives (x - 5)^1. Sum = 3 + 1 + 1 = 5, odd, matching opposite end behavior. Right end rises means positive leading coefficient, so a = 1. Degree 5.

Check: Check that the sum of exponents is 5 and that the right end rises for positive leading coefficient; verify intercepts at -3, 0, 5.

Exercise 3

A polynomial graph touches at x = -2 and touches at x = 3. Both ends fall. The graph passes through (0, -36). Write a factored equation and state the degree.

Show answer and check

f(x) = -(x + 2)^2(x - 3)^2, degree 4.

Why: Touch at -2 gives (x + 2)^2; touch at 3 gives (x - 3)^2. Sum = 4, even, matching both ends falling. Both ends fall means negative leading coefficient. Substitute (0, -36): -36 = a(2)^2(-3)^2 = a(4)(9) = 36a, so a = -1. Degree 4.

Check: Substitute x = 0 to confirm -36; confirm even degree and negative leading coefficient produce both ends falling.

Exercise 4

A polynomial graph crosses at x = -4, touches at x = -1, and crosses at x = 2. Both ends fall. The graph passes through (0, 4). Write a factored equation and state the degree.

Show answer and check

f(x) = -(1/2)(x + 4)(x + 1)^2(x - 2), degree 4.

Why: Cross at -4 gives (x + 4); touch at -1 gives (x + 1)^2; cross at 2 gives (x - 2). Sum = 1 + 2 + 1 = 4, even, matching both ends falling. Both ends fall means negative leading coefficient. Substitute (0, 4): 4 = a(4)(1)(-2) = -8a, so a = -1/2. Degree 4.

Check: Substitute x = 0 to confirm 4; confirm even degree and negative leading coefficient give both ends falling.

Common mistakes

Self-check rubric

Questions and answers

How do I know if an intercept has multiplicity 2 or 4?

Both are even and produce a touch. Without more shape information, choose the smallest even multiplicity, 2. A flatter touch may suggest 4, but only if the graph clearly shows extra flattening.

Can a graph cross the x-axis at a root with even multiplicity?

No. Even multiplicity means the graph touches and turns back without crossing. Odd multiplicity means it crosses.

What if the graph has no visible x-intercepts?

Then there are no real roots, so the factored form over real numbers has no linear factors. Such graphs are outside the scope of this lesson's intercept-based method.

Do I always need to expand the equation?

No. Factored form is usually preferred because it directly shows roots and multiplicities. Expand only when the task explicitly requests expanded form.

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