HomeBalance-Scale Algebra: Solving for Unknown Weights Free original lessons
Balance-Scale Algebra: Solving for Unknown Weights
Learn to translate balance-scale diagrams into equations and solve for one or two unknown weights using simple, checkable arithmetic.
Free lesson
Four exercises
Worked answers
Algebra and Function Practice
Balance-scale diagrams turn abstract equations into a visual puzzle: the scale stays level only when both sides have equal total weight. In this lesson you will read a diagram, assign a variable to each unknown shape, write an equation that matches the balanced state, and solve it step by step. You will also learn to check your answer by substituting it back into the diagram. The convention used here is that every identical shape has the same weight, and any number printed on a shape or block is its weight in grams. All numerical values in examples are hypothetical teaching values, not measurements of real equipment.
Practice materials: Printable downloads are not available for this lesson yet. Use the instructions and four exercises below.
Reading a Balance-Scale Diagram
A balance-scale diagram shows a horizontal beam with a pan or platform on each side. When the beam is level, the total weight on the left equals the total weight on the right. Each shape represents an unknown weight, and identical shapes have identical weights. A labeled block shows a known weight in grams.
To read the diagram, list what is on each side. For example, if the left side has three identical circles and the right side has one 12-gram block, then three circles weigh 12 grams in total. If the left side has two squares plus a 5-gram block and the right side has one 17-gram block, then two squares plus 5 grams equals 17 grams.
The key habit is to write the equation before solving. Let a circle be c grams and a square be s grams. The first example gives 3c = 12, and the second gives 2s + 5 = 17. Writing the equation first keeps the diagram and the arithmetic connected.
- Name each unknown shape with a letter variable.
- Write the total weight of the left side as an expression.
- Write the total weight of the right side as an expression.
- Set the two expressions equal because the beam is level.
- Solve the equation and state the weight of one shape.
Solving One-Unknown Balance Problems
When only one shape type is unknown, the equation usually has the form a times the variable plus or minus a known weight equals a known total. Undo the added or subtracted weight first, then divide by the number of shapes.
For instance, suppose the left side has four identical triangles and a 6-gram block, and the right side has a 30-gram block. Let t be the weight of one triangle. The equation is 4t + 6 = 30. Subtract 6 from both sides to get 4t = 24, then divide by 4 to get t = 6 grams.
Always check by substitution: four triangles at 6 grams each weigh 24 grams, plus the 6-gram block gives 30 grams, which matches the right side. This check catches arithmetic slips and confirms the equation matched the diagram.
- Subtract or add the known weight on the same side as the unknown shapes.
- Divide the remaining total by the number of identical shapes.
- Substitute the result back into the original diagram description.
- Confirm both sides have equal total weight.
Two-Unknown Balance Problems
Some diagrams show two different unknown shapes, such as circles and squares. A single balanced scale gives one equation with two unknowns, which usually has many numerical solutions. To find a unique pair, you need a second balanced scale or an extra condition, such as a stated relationship between the two shapes.
For example, scale one shows one circle and one square balancing a 20-gram block, so c + s = 20. Scale two shows two circles and one square balancing a 28-gram block, so 2c + s = 28. Subtracting the first equation from the second gives c = 8, and then s = 12. Check: 8 + 12 = 20 and 16 + 12 = 28.
When no second scale is given, do not invent a unique answer. Instead, describe the family of solutions, such as s = 20 minus c for any positive c, and explain what extra information would pin down one value.
- Write one equation for each balanced scale.
- Compare the equations to eliminate one variable, often by subtracting.
- Solve for the remaining variable.
- Substitute back into either equation to find the other variable.
- Check both original scales with the pair of values.
Checking and Communicating Answers
A complete answer states the variable definition, the equation, the solution, and a substitution check. Units matter: if blocks are labeled in grams, the unknown weights are in grams. Keep the same unit throughout and do not mix grams with kilograms without converting.
When a diagram is described in words rather than drawn, restate the description in your own equation before solving. This makes your reasoning easy to follow and easy to check. If a result is not a whole number, keep it as a fraction or decimal and verify by substitution rather than rounding early.
- State what each variable represents and its unit.
- Show the equation that matches the diagram.
- Show each solving step on its own line.
- Substitute the answer into both sides and compare totals.
Worked example
A balance scale is level. The left side has three identical circles and a 4-gram block. The right side has a 19-gram block. Find the weight of one circle.
Worked answer
One circle weighs 5 grams.
Why: Let c be the weight of one circle in grams. The left side weighs 3c + 4 grams and the right side weighs 19 grams. Since the scale is level, 3c + 4 = 19. Subtract 4 from both sides: 3c = 15. Divide by 3: c = 5. Check: three circles weigh 15 grams, plus 4 grams gives 19 grams, matching the right side.
Four practice exercises
Exercise 1
A level balance scale has two identical squares and a 7-gram block on the left, and a 25-gram block on the right. Find the weight of one square.
Show answer and check
One square weighs 9 grams.
Why: Let s be the weight of one square. The left side is 2s + 7 and the right side is 25, so 2s + 7 = 25. Subtract 7: 2s = 18. Divide by 2: s = 9. Check: two squares weigh 18 grams, plus 7 grams gives 25 grams.
Check: Substitute 9 into the left side: 2 times 9 plus 7 equals 25, which matches the right side.
Exercise 2
A level balance scale has five identical triangles on the left and a 35-gram block on the right. Find the weight of one triangle.
Show answer and check
One triangle weighs 7 grams.
Why: Let t be the weight of one triangle. The equation is 5t = 35. Divide both sides by 5: t = 7. Check: five triangles at 7 grams each weigh 35 grams, matching the right side.
Check: Multiply 5 by 7 and confirm the result is 35 grams.
Exercise 3
Scale one is level with one circle and one square on the left and a 20-gram block on the right. Scale two is level with two circles and one square on the left and a 28-gram block on the right. Find the weight of one circle and one square.
Show answer and check
One circle weighs 8 grams and one square weighs 12 grams.
Why: Let c be a circle's weight and s a square's weight. Scale one gives c + s = 20. Scale two gives 2c + s = 28. Subtracting the first equation from the second gives c = 8. Then 8 + s = 20, so s = 12. Check: 8 + 12 = 20 and 16 + 12 = 28.
Check: Substitute c = 8 and s = 12 into both scale equations and confirm each side equals the stated total.
Exercise 4
A level balance scale has one circle and one square on the left and a 30-gram block on the right. No second scale is given. Describe all possible whole-number weights for the circle and square, and explain why one unique answer cannot be found.
Show answer and check
The circle and square weights must be positive whole numbers that add to 30, such as 1 and 29, 10 and 20, or 15 and 15. A unique answer cannot be found because one equation with two unknowns has many solutions.
Why: Let c be the circle's weight and s the square's weight. The only equation is c + s = 30. For each positive whole-number choice of c, s is 30 minus c. Without a second balanced scale or an extra condition relating c and s, many pairs satisfy the diagram.
Check: Pick any listed pair, add the two weights, and confirm the sum is 30 grams. Then confirm that a different pair also sums to 30, showing the answer is not unique.
Common mistakes
- Adding the known block to the total instead of subtracting it when the block is on the same side as the unknown shapes. Identify which side contains the unknown shapes. Undo the known weight on that side by subtracting it from both sides before dividing.
- Treating different shapes as having the same weight without being told. Use a separate variable for each different shape. Only identical shapes share a variable.
- Giving a single numerical answer for a two-unknown diagram that provides only one balanced scale. Recognize that one equation with two unknowns has many solutions. State the relationship and explain what second condition is needed.
- Forgetting to divide by the number of identical shapes after subtracting the known weight. After isolating the total weight of the identical shapes, divide by how many there are to find one shape's weight.
Self-check rubric
- Defines each variable clearly and states its unit.
- Writes an equation that correctly matches the balanced diagram.
- Shows solving steps in a logical order with correct arithmetic.
- Substitutes the answer back into the diagram description to check.
- For two-unknown problems, uses both scales or states the family of solutions when only one scale is given.
- Accepts equivalent correct forms such as fractions or decimals when the value is not a whole number.
Questions and answers
Do identical shapes always have the same weight?
Yes, in these balance-scale problems identical shapes represent equal unknown weights. Different shapes get different variables unless the problem states otherwise.
What if the answer is not a whole number?
That is acceptable. Keep the fraction or decimal and check by substitution. Do not round unless the problem asks for a rounded value.
Why do I need two scales for two unknowns?
One balanced scale gives one equation. With two unknowns, one equation usually has many solutions. A second scale or an extra condition provides the second equation needed for a unique pair.
How do I check my answer quickly?
Substitute the weight back into the diagram description and compute both sides. If the totals match, the answer is consistent with the diagram.