HomeGrade 7 Equation Word Problems: Define the Variable First Free original lessons
Grade 7 Equation Word Problems: Define the Variable First
Teach students to define a variable, write a one-variable equation, and solve grade-7 word problems with a clear template and practice.
Free lesson
Four exercises
Worked answers
Algebra and Function Practice
Many grade-7 students can solve an equation once it is written but struggle to turn a word problem into one. The reliable first move is to define the variable in words, state what it represents and its unit, then write an equation that matches the story. This lesson gives a repeatable three-step template, a worked example, common mistake fixes, and four self-contained practice tasks. All arithmetic uses consistent units and simple checkable values. A printable worksheet and answer key are planned but not yet built; the resource plan below describes what will be produced.
Practice materials: Printable downloads are not available for this lesson yet. Use the instructions and four exercises below.
The define-variable template
Use the same three-line template for every problem: Define, Write, Solve. In the Define line, name the unknown in words and include its unit, for example 'Let n be the number of notebooks.' Avoid vague labels like x without meaning. In the Write line, translate each phrase into an operation and connect the parts with an equals sign. In the Solve line, perform inverse operations one at a time and keep the equation balanced.
A strong definition prevents most errors. If a problem asks for two quantities, define the smaller or base quantity first and express the other in terms of it. For example, if a rope is cut into two pieces and one is 3 feet longer, define the shorter piece as s feet and write the longer piece as s + 3 feet. Then the equation uses one variable only.
- Read the problem twice and underline the unknown quantity and its unit.
- Write 'Let ___ be ___' using a word name and unit.
- Translate the relationship into an equation with one variable.
- Solve using inverse operations, showing each step.
- Substitute the solution back into the word problem to check meaning and units.
Translating words into equations
Certain phrases map to operations. 'More than' and 'increased by' suggest addition; 'less than' and 'decreased by' suggest subtraction, but order matters: '5 less than a number' is n - 5, not 5 - n. 'Times' and 'product' suggest multiplication; 'per' and 'divided equally' suggest division. 'Is' or 'equals' marks the equals sign.
Keep units visible in the equation. If a problem mixes dollars and cents, convert to one unit first. If it mixes hours and minutes, convert to minutes or hours before writing the equation. Consistent units make the check meaningful and prevent silent errors.
- Circle operation words and write the matching symbol above them.
- Convert all quantities to one unit before writing the equation.
- Place the equals sign where the word 'is' or 'equals' appears.
- Check that both sides of the equation describe the same total or relationship.
Checking the solution in context
A solution is not finished until it is checked against the story. Substitute the value into the original word relationship, not just the equation. Ask whether the answer is reasonable: a number of people must be a whole number, a length must be positive, and a total cost must match the given budget.
Use a quick arithmetic check. If the equation is 4n + 7 = 35, then n = 7 because 4 times 7 is 28 and 28 plus 7 is 35. In context, if n is notebooks costing 4 dollars each plus a 7-dollar fee, the total is 35 dollars, which matches. State the check in one sentence with units.
- Substitute the solution into the original word relationship.
- Compute both sides separately and compare.
- Confirm the unit and reasonableness of the answer.
- Write a final answer sentence that includes the unit.
Worked example
A school store sells notebooks for 4 dollars each and charges a one-time 7-dollar fee for a bulk order. A class spends 35 dollars. How many notebooks did the class order? Define the variable, write an equation, and solve.
Worked answer
Let n be the number of notebooks. The cost is 4n + 7 dollars, which equals 35 dollars. So 4n + 7 = 35. Subtract 7 from both sides: 4n = 28. Divide both sides by 4: n = 7. Check: 4 times 7 is 28, and 28 plus 7 is 35, which matches the total. The class ordered 7 notebooks.
Four practice exercises
Exercise 1
A rope is cut into two pieces. One piece is 3 feet longer than the other, and the total length is 15 feet. Define the variable, write an equation, and find the length of each piece.
Show answer and check
The shorter piece is 6 feet and the longer piece is 9 feet.
Why: Let s be the length of the shorter piece in feet. The longer piece is s + 3 feet. The total is s + (s + 3) = 15. Combine like terms: 2s + 3 = 15. Subtract 3: 2s = 12. Divide by 2: s = 6. The longer piece is 6 + 3 = 9 feet. Check: 6 + 9 = 15 feet.
Check: Substitute 6 into the original relationship: 6 + (6 + 3) = 15, which matches the total. Confirm both lengths are positive and in feet.
Exercise 2
A class buys pencils that cost 2 dollars each and pays a 5-dollar delivery fee. The total cost is 21 dollars. Define the variable, write an equation, and find the number of pencils.
Show answer and check
The class bought 8 pencils.
Why: Let p be the number of pencils. The cost is 2p + 5 dollars, which equals 21 dollars. So 2p + 5 = 21. Subtract 5: 2p = 16. Divide by 2: p = 8. Check: 2 times 8 is 16, and 16 plus 5 is 21.
Check: Substitute 8 into the cost relationship: 2(8) + 5 = 21, which matches the total. Confirm the answer is a whole number because pencils are countable.
Exercise 3
A number is multiplied by 3, then 4 is subtracted. The result is 20. Define the variable, write an equation, and find the number.
Show answer and check
The number is 8.
Why: Let n be the number. Three times the number is 3n. Subtracting 4 gives 3n - 4. The result is 20, so 3n - 4 = 20. Add 4 to both sides: 3n = 24. Divide by 3: n = 8. Check: 3 times 8 is 24, and 24 minus 4 is 20.
Check: Substitute 8 into the original operations: 3(8) - 4 = 20, which matches the result. Confirm the order of operations matches the story.
Exercise 4
A rectangle has a length that is 2 meters more than its width. The perimeter is 20 meters. Define the variable, write an equation, and find the width and length.
Show answer and check
The width is 4 meters and the length is 6 meters.
Why: Let w be the width in meters. The length is w + 2 meters. Perimeter is 2w + 2(w + 2) = 20. Expand: 2w + 2w + 4 = 20. Combine: 4w + 4 = 20. Subtract 4: 4w = 16. Divide by 4: w = 4. The length is 4 + 2 = 6 meters. Check: 2(4) + 2(6) = 8 + 12 = 20 meters.
Check: Substitute 4 and 6 into the perimeter formula: 2(4) + 2(6) = 20, which matches. Confirm the length is 2 meters more than the width and both are positive.
Common mistakes
- Defining the variable without a unit or word meaning, such as 'Let x be the answer.' Write a full definition: 'Let n be the number of notebooks.' Include the unit and what is counted.
- Reversing subtraction phrases, writing 5 - n for '5 less than a number.' Translate 'less than' by starting with the unknown: n - 5. Say the phrase aloud in order.
- Mixing units, such as adding dollars to cents without converting. Convert all quantities to one unit before writing the equation, then label the unit in the definition.
- Solving correctly but not checking the answer in the story. Substitute the value into the original relationship and confirm the total and unit match the problem.
Self-check rubric
- Defines the variable in words with a unit.
- Writes a one-variable equation that matches the word relationship.
- Solves using inverse operations with each step shown.
- Checks the solution in the original context and states the answer with units.
- Uses consistent units throughout the work.
Questions and answers
Why define the variable before writing the equation?
A clear definition tells you what the variable measures and its unit, which makes translation and checking easier. It also prevents using the same letter for two different quantities.
What if the problem has two unknown quantities?
Define the base or smaller quantity first, then express the other in terms of it. For example, if one piece is 3 feet longer, let the shorter piece be s feet and the longer piece be s + 3 feet.
How do I know which operation a phrase means?
Underline operation words and write the symbol above them. 'More than' means addition, 'less than' means subtraction with the unknown first, 'times' means multiplication, and 'divided equally' means division.
Is a whole-number answer always required?
Only when the quantity must be countable, such as people or notebooks. Lengths and costs can be decimals, but check that the value is reasonable for the story.