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Writing Exponential Functions from Tables and Graphs: A Structured Guide

Learn to derive exponential equations from tables and graphs by identifying initial value and growth or decay factor, with worked examples and practice.

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Four exercises
Worked answers

Algebra and Function Practice

Exponential functions model growth and decay. From a table or graph, you can write the function y = a · b^x by finding the initial value a (the y-intercept) and the base b (the constant ratio). This guide shows a reliable method, common pitfalls, and four practice tasks with full reasoning and checks.

Practice materials: Printable downloads are not available for this lesson yet. Use the instructions and four exercises below.

Core Idea: Initial Value and Constant Ratio

An exponential function has the form y = a · b^x, where a is the initial value (value at x = 0) and b is the growth or decay factor. For b > 1, the function grows; for 0 < b < 1, it decays.

In a table, consecutive y-values have a constant ratio equal to b when x increases by 1. In a graph, the y-intercept gives a, and the ratio between y-values at x = 0 and x = 1 gives b.

Always verify with a check point not used to find a or b.

  1. Identify the y-intercept from the table (x = 0) or graph (where the curve crosses the y-axis). That y-value is a.
  2. Compute the ratio b = y(x+1) / y(x) for consecutive x-values. Confirm the ratio is constant.
  3. Write y = a · b^x.
  4. Substitute a check point to verify.

From a Table: Finding a and b

If the table includes x = 0, read a directly. If not, use two points to solve for b, then back-substitute to find a.

For example, if y doubles each step and y(0) = 3, then a = 3 and b = 2, so y = 3 · 2^x.

When x-values are not consecutive, adjust: b = (y2/y1)^(1/(x2−x1)).

  1. Check for x = 0 to get a.
  2. Compute ratios for consecutive x-values; confirm constant b.
  3. If x = 0 is missing, use two points: b = (y2/y1)^(1/(x2−x1)), then a = y1 / b^(x1).
  4. Write the function and verify with another point.

From a Graph: Reading the Intercept and Ratio

Locate the y-intercept (0, a). Then find another clear point at x = 1 to compute b = y(1)/a. If x = 1 is not marked, use any two clear points and the formula b = (y2/y1)^(1/(x2−x1)).

Graphs may show decay (b between 0 and 1) or growth (b > 1). Ensure the curve is smooth and points are read accurately.

Verify by checking a third point on the graph.

  1. Read the y-intercept to get a.
  2. Read a second point, preferably at x = 1, to compute b.
  3. If needed, use two non-consecutive points with the ratio formula.
  4. Write y = a · b^x and check with a third point.

Verification and Common Variations

Always substitute a check point. If the computed y matches, the function is consistent with the data.

Tables may use negative x-values; the same ratio method applies. Graphs may have axes scaled differently; read coordinates carefully.

If the ratio is not constant, the data may not be exponential; do not force a model.

  1. Choose a point not used in finding a or b.
  2. Substitute x into your function and compare with the given y.
  3. If mismatch, recheck ratios and intercept.
  4. State the final function clearly.

Worked example

A table shows (0, 5), (1, 15), (2, 45), (3, 135). Write the exponential function.

Worked answer

y = 5 · 3^x

Four practice exercises

Exercise 1

Table: (0, 2), (1, 6), (2, 18), (3, 54). Write the exponential function.

Show answer and check

y = 2 · 3^x

Why: At x = 0, y = 2, so a = 2. Ratio 6/2 = 3, 18/6 = 3, 54/18 = 3, so b = 3. Function: y = 2 · 3^x. Check x = 2: 2 · 3^2 = 18, matches.

Check: Substitute x = 3: 2 · 3^3 = 54, matches table.

Exercise 2

Table: (1, 12), (2, 6), (3, 3), (4, 1.5). Write the exponential function.

Show answer and check

y = 24 · (1/2)^x

Why: Ratio 6/12 = 1/2, 3/6 = 1/2, 1.5/3 = 1/2, so b = 1/2. Use point (1, 12): 12 = a · (1/2)^1 → a = 24. Function: y = 24 · (1/2)^x. Check x = 2: 24 · (1/2)^2 = 6, matches.

Check: Substitute x = 4: 24 · (1/2)^4 = 1.5, matches table.

Exercise 3

Graph description: A smooth curve crosses the y-axis at (0, 4) and passes through (1, 10) and (2, 25). Write the exponential function.

Show answer and check

y = 4 · 2.5^x

Why: y-intercept gives a = 4. Using (1, 10): 10 = 4 · b^1 → b = 2.5. Check with (2, 25): 4 · 2.5^2 = 4 · 6.25 = 25, matches. Function: y = 4 · 2.5^x.

Check: Substitute x = 1: 4 · 2.5 = 10, matches graph point.

Exercise 4

Graph description: A decaying curve crosses the y-axis at (0, 8) and passes through (1, 4) and (2, 2). Write the exponential function.

Show answer and check

y = 8 · (1/2)^x

Why: y-intercept gives a = 8. Using (1, 4): 4 = 8 · b^1 → b = 1/2. Check with (2, 2): 8 · (1/2)^2 = 2, matches. Function: y = 8 · (1/2)^x.

Check: Substitute x = 2: 8 · (1/2)^2 = 2, matches graph point.

Common mistakes

Self-check rubric

Questions and answers

What if the table does not include x = 0?

Compute b from ratios, then find a by back-substituting a known point: a = y / b^x.

How do I know if it is growth or decay?

If b > 1, it is growth; if 0 < b < 1, it is decay.

Can I use any two points to find b?

Yes, using b = (y2/y1)^(1/(x2−x1)), provided the points are on the same exponential curve.

What if the ratio is not constant?

The data may not be exponential; do not force an exponential model.

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