Free graphing resources · Original practice

Midpoint and distance.
One segment, two calculations.

Find a segment midpoint by averaging coordinates, then calculate its straight-line distance. Compare ordinary, vertical, fractional and coincident-endpoint cases.

6 endpoint pairs.
Exact radicals + worked answers.

A graph, a task and a worked check

Find a segment midpoint by averaging coordinates, then calculate its straight-line distance. Compare ordinary, vertical, fractional and coincident-endpoint cases.

Use the student pack for an attempt, then compare the separate reference or worked answer. Every case is original. All PDF and editable SVG resources are free without signup; each collection pack repeats its individual sheets in the same order.

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The complete collection

Keep practice and answers separate.

Use the student pack first, then compare the reference or answer. Packs are PDFs; individual sheets below also include editable SVG files. The paper choice applies to every download.

6 pages per file · free · CC BY 4.0

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US Letter
A4

Choose a specific case

CaseFocus
MD01A six-by-eight displacement
MD02An eight-by-six displacement
MD03A fractional midpoint
MD04A vertical segment
MD05An irrational distance
MD06Coincident endpoints

The examples and datasets are made for these worksheets. They are not measured classroom results, published textbook questions or evidence about real people. Axis values and the supplied data determine the answers; paper measurements do not replace those numbers.

Check the first case

MD01: A six-by-eight displacement

CheckWorked result
1(-1,2).
2dx=6, dy=8; dx^2+dy^2=100.
310 units.

The table gives one worked case so you can check the method. The separate answer files contain the completed plots and results for every case. An exact radical is preferred; label a decimal distance as approximate.

Work through the graph

  1. Confirm the endpoints already supplied The student sheet gives A and B as coordinates and as plotted markers joined by their segment. Confirm the numbers before finding a new point. In MD01, A=(-4,-2) and B=(2,6); the coordinate changes from A to B are 6 horizontally and 8 vertically. The reference adds the midpoint and an axis-aligned construction guide. Keep that file aside while calculating. In MD06 the endpoints coincide, so one location is marked A=B; a missing visible segment is the intended zero-length case, not an instruction to invent another endpoint.
  2. Calculate Midpoint Coordinates Determine the midpoint by averaging the corresponding x and y coordinates of the endpoints. For case MD03, average negative three and one for the x-coordinate, and negative one and two for the y-coordinate. This yields a fractional midpoint, which is a specific feature of this exercise set. Remember that the midpoint is simply the arithmetic mean of the positions. Do not measure physical distances on the paper, as the answers rely on digital unit calculations. If endpoints coincide, as in case MD06, the midpoint remains identical to the endpoints. This method ensures consistency across all fictional examples without requiring physical ruler measurement.
  3. Compute Euclidean Distance Apply the distance formula using the differences in x and y coordinates. Calculate the square root of the sum of the squared differences. For case MD05, the result is an irrational number, so prefer the exact radical form over a decimal approximation. If you provide a decimal, label it as about to indicate approximation. The distance is always nonnegative. In case MD06, where endpoints coincide, the distance is zero. Note that these distances represent axis units, not millimeters on the printed page. This distinction prevents errors from physical printer scaling issues, as no physical printer checks have been performed for these digital resources.

Checks that catch common errors

Watch forCheck instead
Measuring the printed line with a physical ruler to determine distance.Use the coordinate differences and the distance formula, as answers depend on digital units, not physical paper measurements.
Rounding an irrational distance to a decimal without labeling it as approximate.Prefer the exact radical form, or if using a decimal, explicitly label it as about to indicate approximation.
Assuming the midpoint is always an integer coordinate.Calculate the average of the coordinates, which may result in fractional values as seen in case MD03.

Keep the labels and margins readable

Choose the Letter or A4 file that matches your paper. Actual size / 100% preserves the designed layout; a different uniform print scale changes physical lengths but does not change the listed numbers or the arithmetic. Keep the whole chart and all labels inside the printable area. A ruler can help draw straight segments, but calculate from the stated numerical scale.

These files have digital geometry, arithmetic and page-boundary checks. Physical printer and classroom trials have not been completed. The resources are practice material, with no claim of curriculum certification or precision-instrument accuracy. The original files use CC BY 4.0: credit Zumola, link the license and indicate changes.

Useful answers

Can a midpoint have fractional coordinates?

Yes. Average each coordinate pair separately. MD03 has midpoint (-1,1/2), even though both endpoints use integer coordinates.

Is the distance the same as adding horizontal and vertical changes?

No. The straight-line distance is the square root of dx squared plus dy squared. Adding absolute changes instead measures an axis-aligned route, generally a longer path.

What if the endpoints coincide?

The midpoint is that same point and the distance is zero. MD06 deliberately includes this case; it is not a missing segment.

Are the answer files and editable graphs free?

Yes. Reference, student and worked-answer files are all free without an account. Single sheets include PDF and SVG; collection packs are PDF files. Analytics consent is not required to download.

Keep plotting

Further reading: OpenStax: distance and midpoint formulas. The data tables, illustrations and exercise cases here are original Zumola work.

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